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Chandelier Exit Variation II
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| Added: January 26, 2007 |
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MetaStock, system
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Re: Formula Question
· To: <metastock@xxxxxxxxxxxxx>
· Subject: Re: Formula Question
· From: "Barry Marx" <bmarx@xxxxxxxxx>
· Date: Sun, 20 Feb 2000 21:23:32 -0500
· References: <NBBBJEOJKICGFFHPBAHKAEKPDGAA.hardy@xxxxxxxxxxxxx>
· Reply-To: metastock@xxxxxxxxxxxxx
· Sender: owner-metastock@xxxxxxxxxxxxx
Below is a variation of the Chandelier Exit that I came up with. It doesn't
solve the original question, but I like the way it plots better.It holds the
highest value every time the stop moves up, and never moveslower unless the
stop is hit, in which case its value is reset.
- Barry
Code:
Chandelier Exit Variation II
Stop1:=If( PREV < L,
{then} If(( H - 3*ATR(10) ) >= PREV,
{then} ( H - 3*ATR(10) ),
{else} PREV),
{else (L <= PREV)}
( H - 3*ATR(10) ));
Stop2:=If( PREV < L,
{then} If(( C - 2.5*ATR(10) ) >= PREV,
{then} ( C - 2.5*ATR(10) ),
{else} PREV),
{else (L <= PREV)}
( C - 2.5*ATR(10) ));
StopVal:=If(Stop1>Stop2,Stop1,Stop2);
StopVal;
Code to difficult? Find somebody to help you with coding here.
Source: http://purebytes.com/archives/metastock/
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